【PAT】B1002 写出这个数

思路：
1.以字符串形式输入数据，计算结果
2.使用sprintf将结果数字转换为字符串（将数字每一位分开）
3.分别输出字符每一位

1，笨方法，用的ifelse来判断输出

#include<stdio.h>
#include<string.h>
char arr[110];

int getsum() {
    int sum = 0;
    int len = strlen(arr);
    for (int i = 0; i<len; i++) {
        sum += arr[i] - '0';
    }
    return sum;
}
int main() {
    scanf("%s", arr);
    int sum = getsum();
    sprintf(arr, "%d", sum);
    int len = strlen(arr);
    for (int i = 0; i<len; i++) {
        if (i != 0) printf(" ");
        if (arr[i] == '1')
            printf("yi");
        else if (arr[i] == '2')
            printf("er");
        else if (arr[i] == '3')
            printf("san");
        else if (arr[i] == '4')
            printf("si");
        else if (arr[i] == '5')
            printf("wu");
        else if (arr[i] == '6')
            printf("liu");
        else if (arr[i] == '7')
            printf("qi");
        else if (arr[i] == '8')
            printf("ba");
        else if (arr[i] == '9')
            printf("jiu");
        else if (arr[i] == '0')
            printf("ling");
    }
    return 0;
}

2，简化代码，用如下代码简化输出部分的ifelse结构

char data[10][20] = { "ling","yi","er","san","si","wu","liu","qi","ba","jiu" };
printf("%s", data[arr[i] - '0']);