每日一练之Remove Element【LeetCode No.27】—删除数组相应值
Given an array and a value, remove all instances of that value in place and return the new length.
Do not allocate extra space for another array, you must do this in place with constant memory.
The order of elements can be changed. It doesn't matter what you leave beyond the new length.
Example:
Given input array nums = [3,2,2,3], val = 3
Your function should return length = 2, with the first two elements of nums being 2.
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//分析：删除数组中值为val的所有数，返回新长度。可以用两个指针，一个为可放位置指针，一个为扫描指针。
class Solution {
public:int removeElement(vector<int>& nums, int val) {
int start=0;
int n=nums.size();
for(int i=0;i<n;i++)
if(nums[i]!=val){
nums[start++]=nums[i];
}
return start;
}
};
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