题解

python 实现。自己的一点小思路，欢迎指正。主要利用了list中的元素互不相同的特性

class Solution:
    def IsPopOrder(self, pushV, popV):
        # write code here
        if not pushV and not popV:
            return True
        if not pushV or not popV:
            return False

        popV_copy=popV[:]
        for i in pushV:
            if i not in popV_copy:
                return False
            else:
                popV_copy.remove(i)

        start = popV[0]
        start_index = pushV.index(start)
        for i in range(start_index):
            if popV.index(pushV[i])<popV.index(pushV[i+1]):
                return False
        return True