华为机试-记负均正(HJ105)-纯C
记负均正II
http://www.nowcoder.com/questionTerminal/64f6f222499c4c94b338e588592b6a62
纯C
这题不应该归为较难的把,属于简单的吧!
#include <stdio.h>
#include <string.h>
int main()
{
int num, cnt1=0, cnt2=0, sum=0;
while(scanf("%d",&num) != EOF)
{
if(num < 0)
{
cnt1++;
}
else
{
sum += num;
cnt2++;
}
}
float result =(cnt2>0)?((float) sum / cnt2):0;
printf("%d\n%0.1f\n",cnt1,result);
return 0;
}

