题解 | #牛客每个人最近的登录日期(三)#
牛客每个人最近的登录日期(三)
http://www.nowcoder.com/practice/16d41af206cd4066a06a3a0aa585ad3d
所有跨日期登陆的都记为1，然后去重，最后统计
select round(sum(rank)*1.0/count(distinct user_id),3) from (select distinct user_id,rank from (select t1.user_id,t1.date,t2.date,case when date(t1.date,'+1 day')=t2.date then 1 else 0 end as rank from login t1 join login t2 on t1.user_id=t2.user_id)) as t3
投递阿里云等公司10个岗位
就算你真拿到牛友也会为你开心的