题解 | #回文数字#

    public boolean isPalindrome (int x) {
        // write code here
        if (x < 0) return false;
        int count = 0, a = x;
        while (a != 0){
            a /= 10;
            count++;
        }
        int l = 1, r = (int)Math.pow(10, count-1);
        while (l < r){
            int low = x/l%10;
            int high = x/r%10;
            if (low != high) return false;
            l *= 10;
            r /= 10;
        }
        return true;
    }