题解 | #字符串排序#
字符串排序
http://www.nowcoder.com/practice/5af18ba2eb45443aa91a11e848aa6723
while True:
try:
num=int(input())
stack=[]
for i in range(num):
stack.append(input())
print("\n".join(sorted(stack)))
except:
break
投递字节跳动等公司6个岗位
