题解 | #把字符串转换成整数(atoi)#
把字符串转换成整数(atoi)
http://www.nowcoder.com/practice/d11471c3bf2d40f38b66bb12785df47f
# # 代码中的类名、方法名、参数名已经指定,请勿修改,直接返回方法规定的值即可 # # # @param s string字符串 # @return int整型 # class Solution: def StrToInt(self , s: str) -> int: # write code here s = s.strip() if not s: return 0 sign = -1 if s[0] == '-' else 1 if s[0] == '-' or s[0] == '+': s = s[1:] num = 0 for i in s: if i.isdigit(): num *= 10 num += ord(i) - 48 else: break return min(max(sign * num, -2 ** 31), 2 ** 31 - 1)
