题解 | #获得积分最多的人(一)#
获得积分最多的人(一)
http://www.nowcoder.com/practice/1bfe3870034e4efeb4b4aa6711316c3b
SELECT name ,t
FROM user u
RIGHT JOIN
(SELECT user_id,SUM(grade_num) OVER (PARTITION BY user_id) t
FROM grade_info
ORDER BY t DESC
LIMIT 1) a
ON u.id = a.user_id
ORDER BY t DESC
