题解 | #简易秒表#
简易秒表
http://www.nowcoder.com/practice/6493ca8c7b67499f918e1fa33b4cdeda
题解主体
首先确定second的取值逻辑：当minute=60时停止计数，即保持second为0；当second=60时，下一个周期second置为1。其余情况second 等于前一时刻的值加一。
always @(posedge clk or negedge rst_n)
if (!rst_n)
begin
second <= 6'd0;
end
else if(second == 6'd60)
begin
second <= 6'd1;
end
else if (minute == 60)
second <= second;
else
second <= second+1'd1;
然后明确minute的取值逻辑：当second=60，minute等于前一时刻的值加一。其余情况，minute保持不变。
always @(posedge clk or negedge rst_n)
if (!rst_n)
begin
minute <= 6'd0;
end
else if (second == 6'd60)
begin
minute <= minute+1;
end
else
begin
minute <= minute;
end
参考答案
`timescale 1ns/1ns module count_module( input clk, input rst_n, output reg [5:0]second, output reg [5:0]minute ); always @(posedge clk or negedge rst_n) if (!rst_n) begin minute <= 6'd0; end else if (second == 6'd60) begin minute <= minute+1; end else begin minute <= minute; end always @(posedge clk or negedge rst_n) if (!rst_n) begin second <= 6'd0; end else if(second == 6'd60) begin second <= 6'd1; end else if (minute == 60) second <= 0; else second <= second+1'd1; endmodule
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