题解 | #MP3光标位置#
MP3光标位置
http://www.nowcoder.com/practice/eaf5b886bd6645dd9cfb5406f3753e15
类实现
#include <iostream>
#include <string>
#include <vector>
using namespace std;
class MP3 {
public:
MP3() = default;
MP3(const int &num);
void pressButton(const string &keys);
void showList();
void curSong();
private:
int cursor;
vector<int> list; // 歌曲列表
vector<int> screen; // 屏幕上显示的歌曲
};
int main() {
int num;
cin >> num;
MP3 oppo(num);
string keys;
cin >> keys;
oppo.pressButton(keys);
oppo.showList();
oppo.curSong();
return 0;
}
MP3::MP3(const int &num) {
for (int i = 1; i <= num; i++) {
list.push_back(i);
}
cursor = list[0];
for (int i = 1; i <= (num >= 4 ? 4 : num); i++) {
screen.push_back(i);
}
}
void MP3::pressButton(const string &keys) {
for (auto c : keys) {
if (c == 'U') {
if (cursor == screen[0]) { // 若当前光标是屏幕的第一项
if (screen[0] == list[0]) { // 若屏幕的第一项是列表第一首歌
for (int i = 0; i < screen.size(); i++) {
screen[screen.size() - 1 - i] = list[list.size() - 1 - i];
}
cursor = screen[screen.size() - 1];
}
else {
for (int i = 0; i < screen.size(); i++) {
screen[i] -= 1;
}
cursor -= 1;
}
}
else {
cursor -= 1;
}
}
else if (c == 'D') {
if (cursor == screen[screen.size() - 1]) { // 若当前光标是屏幕的最后一项
if (screen[screen.size() - 1] == list[list.size() - 1]) { // 若屏幕的最后一项是列表最后一首歌
for (int i = 0; i < screen.size(); i++) {
screen[i] = i + 1;
}
cursor = screen[0];
}
else {
for (int i = 0; i < screen.size(); i++) {
screen[i] += 1;
}
cursor += 1;
}
}
else {
cursor += 1;
}
}
}
}
void MP3::showList() {
for (auto l : screen) {
cout << l << " ";
}
cout << endl;
}
void MP3::curSong() {
cout << cursor << endl;
}