题解 | #字符串排序#
字符串排序
http://www.nowcoder.com/practice/5af18ba2eb45443aa91a11e848aa6723
use std::io::{self, *};
fn main() {
let stdin = io::stdin();
let mut num = 0;
let mut v : Vec<String> = vec![];
for line in stdin.lock().lines() {
if num == 0 {
num+=1;
}else{
v.push(line.unwrap());
}
}
v.sort();
for i in 0..v.len(){
println!("{}",v[i]);
}
}
用 Rust 刷华为机试HJ 文章被收录于专栏
用 Rust 刷 HJ100 题，只需要懂基础 Rust 语法就能看懂
