搜狐编程题第二题AC
public static void main(String[] args) {
Scanner in = new Scanner(System.in);
int n = in.nextInt();
int[] nums = new int[n];
for(int i = 0 ; i < n ; i++){
nums[i] = in.nextInt();
}
int min = helper1(nums,n);
System.out.println(min);
}
public static int helper1(int[] nums,int n){
int sum = 0;
for(int num : nums){
sum+=num;
}
int[][] dp = new int[n][n];
for(int j = 0 ; j < n ; j++){
dp[j][j] = nums[j];
for(int i = j-1 ; i >= 0 ; i-- ){
dp[i][j] = Math.max(dp[i+1][j], dp[i][j-1]);
if(nums[j] == nums[i]){
dp[i][j] = Math.max(dp[i][j],dp[i+1][j-1]+nums[j]+nums[i]);
}
}
}
return 2*sum-dp[0][n-1];
} 先求最小回文子序列的最大值,然后用和的两倍减去这个最大值