题解 | #牛牛学数列#
牛牛学数列
http://www.nowcoder.com/practice/0b97367cd2184c12a0e02f7c223aee11
#include<stdio.h>
int main()
{
int n=0,i=0,j=0;;
scanf("%d",&n);
i=n/2;
j=n%2;
if(j==0)
//j=0代表为偶数，则全部抵消；
{
printf("%d",-i);
}
else
//j=1代表为奇数，加上n；
{
printf("%d",n-i);
}
}
