题解 | #删除字符串中出现次数最少的字符#
删除字符串中出现次数最少的字符
http://www.nowcoder.com/practice/05182d328eb848dda7fdd5e029a56da9
字典和字符串处理
字典判定
dic = {}
i in dic
min(dic.values())
字符串替换
str.replace(oud,new)
源代码
s = input()
out = s
dic = {}
for i in s:
if i in dic:
dic[i] = dic[i] + 1
else:
dic[i] = 1
m = min(dic.values())
for i in s:
if dic[i] == m:
out = out.replace(i,'')
print(out)
