题解 | #上三角矩阵判定#
上三角矩阵判定
https://www.nowcoder.com/practice/f5a29bacfc514e5a935723857e1245e4
#include<stdio.h>
int main()
{
int n = 0;
scanf("%d", &n);//表示方阵的n行n列,1≤n≤10
int arr[10][10] = { 0 };
int i = 0;
int j = 0;
for (i = 0; i < n; i++)
{
for (j = 0; j < n; j++)
{
scanf("%d", &arr[i][j]);
}
}
int count = 0;
for (i = 1; i < n; i++)
{
for (j = 0; j < i; j++)
{
if (0 == arr[i][j])
count++;
}
}
if (count == (n * n - n) / 2)
printf("YES\n");
else
printf("NO\n");
return 0;
}

