题解 | #求最大连续bit数#
求最大连续bit数
https://www.nowcoder.com/practice/4b1658fd8ffb4217bc3b7e85a38cfaf2
本题使用滑动窗口的思想，遍历二进制字符串，如果是1，ans = Math.max(ans，++sum)；否则左边界要等于右边界，sum要置0.
import java.util.*;
public class Main {
public static void main(String[] args) {
Scanner sc = new Scanner(System.in);
while (sc.hasNext()) {
int n = sc.nextInt();
String tmp = Integer.toBinaryString(n);
int ans = 0, sum = 0, L = tmp.length();
int start = 0, end = 0;
while (end < L) {
int cur = tmp.charAt(end) - '0';
if (cur == 1) {
sum ++;
ans = Math.max(ans, sum);
} else {
sum = 0;
start = end;
}
end ++;
}
System.out.println(ans);
}
}
}
