题解 | #合并区间#
合并区间
https://www.nowcoder.com/practice/69f4e5b7ad284a478777cb2a17fb5e6a?tpId=295&tqId=691&ru=%2Fpractice%2Fe297fdd8e9f543059b0b5f05f3a7f3b2&qru=%2Fta%2Fformat-top101%2Fquestion-ranking&sourceUrl=%2Fexam%2Foj%3Fpage%3D1%26tab%3D%25E7%25AE%2597%25E6%25B3%2595%25E7%25AF%2587%26topicId%3D295
/**
* Definition for an interval.
* struct Interval {
* int start;
* int end;
* Interval() : start(0), end(0) {}
* Interval(int s, int e) : start(s), end(e) {}
* };
*/
class Solution {
public:
vector<Interval> merge(vector<Interval> &intervals) {
std::vector<Interval> res;
if (intervals.empty()) {
return res;
}
std::sort(intervals.begin(), intervals.end(), [](Interval a, Interval b) -> bool {return a.start < b.start;});
res.push_back(intervals[0]);
for (int i = 1; i < intervals.size(); ++i) {
if (intervals[i].start <= res.back().end) {
res.back().end = std::max(res.back().end, intervals[i].end);
} else {
res.push_back(intervals[i]);
}
}
return res;
}
};
