题解 | #删除字符串中出现次数最少的字符#
删除字符串中出现次数最少的字符
https://www.nowcoder.com/practice/05182d328eb848dda7fdd5e029a56da9
java实现:
1、将字符存入map(字符为key值,value为字符出现次数);
2、找出最小的map.value值;
3、比对字符串与map最小的value值对应的字符,不等则输出;
import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStreamReader;
import java.util.Map;
import java.util.HashMap;
public class Main{
public static void main(String[] args) throws Exception{
BufferedReader read = new BufferedReader(new InputStreamReader(System.in));
String str = read.readLine();
int min = Integer.MAX_VALUE;
Map<Character,Integer> map = new HashMap<Character,Integer>();
for(int i=0;i<str.length();i++){
char c = str.charAt(i);
if(map.containsKey(c)){
map.put(c,map.get(c)+1);
}else{
map.put(c,1);
}
}
for(int j=0;j<str.length();j++){
int val = map.get(str.charAt(j));
if(val<min){
min = map.get(str.charAt(j));
}
}
for(int m=0;m<str.length();m++){
if(map.get(str.charAt(m)) != min){
char ch = str.charAt(m);
System.out.print(str.charAt(m));
}
}
}
}


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