题解 | #链表的奇偶重排#
链表的奇偶重排
https://www.nowcoder.com/practice/02bf49ea45cd486daa031614f9bd6fc3
function oddEvenList( head ) {
if ( !head || !head.next ) {
return head;
}
let odd = head;
let even = head.next;
let evenHead = even;
while ( even && even.next ) {
odd.next = even.next;
odd = odd.next;
even.next = odd.next;
even = even.next;
}
odd.next = evenHead;
return head;
}
