题解 | #牛牛的排序#
牛牛的排序
https://www.nowcoder.com/practice/26a0c92e9266443887a3bf81aff8e188
最基础的冒泡排序
#include<stdio.h>
void sort(int* array,int n)
{
int i = 0, j = 0,tmp = 0;
for(i = 0; i < n - 1; i++)
for(j = 0; j < n - 1 - i; j++)
if(array[j] > array[j + 1])
tmp = array[j], array[j] = array[j + 1], array[j + 1] = tmp;
for(i = 0; i < n; i++)
printf("%d ",array[i]);
printf("\n");
}
int main()
{
int n = 0, i = 0;
int arr[1000] = {0};
scanf("%d",&n);
for(i = 0; i < n; i++)
scanf("%d",arr + i);
sort(arr,n);
return 0;
}

