题解 | #小乐乐改数字#
小乐乐改数字
https://www.nowcoder.com/practice/fcd30aac9c4f4028b23919a0c649824d
#include <stdio.h>
int main() {
int a = 0, b = 0;
scanf("%d", &a);
for (int i = 1; a - i > -1; i = i * 10) {
b += a % (2 * i);
a -= a % (i * 10);
}
printf("%d", b);
return 0;
}
