题解 | #旋转数组的最小数字#
旋转数组的最小数字
https://www.nowcoder.com/practice/9f3231a991af4f55b95579b44b7a01ba
class Solution {
public:
int minNumberInRotateArray(vector<int> rotateArray) {
int left = 0, right = rotateArray.size()-1;
while(left < right)
{
int mid = (left+right) / 2;//取中间值
if(rotateArray[mid] > rotateArray[right]) left = mid+1;//搜索右边
else if(rotateArray[mid] < rotateArray[right]) right = mid;//搜索左边
else right -= 1;
}
return rotateArray[left];
}
};
/*12345
23451
34512
45123
51234*/