题解 | #牛牛学数列#
牛牛学数列
https://www.nowcoder.com/practice/0b97367cd2184c12a0e02f7c223aee11
#include <stdio.h>
int main() {
int n;
scanf("%d",&n);
int i;
if(n%2==0)
{
printf("%d",-1*n/2);
}else{
printf("%d",-1*(n-1)/2+n);
}
return 0;
}
