题解 | #简单密码#
简单密码
https://www.nowcoder.com/practice/7960b5038a2142a18e27e4c733855dac
pw = input()
l2 = [
["a", "b", "c"],
["d", "e", "f"],
["g", "h", "i"],
["j", "k", "l"],
["m", "n", "o"],
["p", "q", "r", "s"],
["t", "u", "v"],
["w", "x", "y", "z"],
]
s = ""
for each in pw:
if each.isupper():
if each == "Z": # 如果是Z直接替换更方便
s += "a"
else:
s += chr(ord(each) + 1).lower() # 通过ASCII码加一位来找到下一个字母
elif each.islower():
for num in l2:
if each in num:
s += str(l2.index(num) + 2) # 利用索引
else:
s += each
print(s)
三奇智元机器人科技有限公司公司福利 70人发布