题解 | #删除链表的节点#

import java.util.*;

/*
 * public class ListNode {
 *   int val;
 *   ListNode next = null;
 *   public ListNode(int val) {
 *     this.val = val;
 *   }
 * }
 */

public class Solution {
    /**
     * 代码中的类名、方法名、参数名已经指定，请勿修改，直接返回方法规定的值即可
     *
     * 
     * @param head ListNode类 
     * @param val int整型 
     * @return ListNode类
     */
    public ListNode deleteNode (ListNode head, int val) {
        // write code here
        ListNode newList = new ListNode(-1);//头结点
        newList.next = head;
        ListNode temp = newList;
        while(head.next != null && head.val != val){
          if(head.next.val == val) temp = head;
          head = head.next;
        }
        if(temp == null){
          return newList.next;
        }else{
          temp.next = head.next;
          return newList.next;
        }
    }
}