题解 | #日期累加#

#include <iostream>
using namespace std;

int GetMonthsDays(int year,int month)
{
    int months[13] = {0,31,28,31,30,31,30,31,31,30,31,30,31};
    if(month==2 && (year%400==0||(year%4==0&&year%100!=0)))
        return 29;
    return months[month];
}

int main() 
{
    int n = 0;
    cin>>n;
    for(int i =0;i<n;++i)
    {
        int year =0,month = 0,day = 0,days = 0;
        cin>>year>>month>>day>>days;
        day+=days;
        while(day>GetMonthsDays(year, month))
        {
            day-=GetMonthsDays(year, month);
            ++month;
            if(month==13)
            {
                ++year;
                month=1;
            }
        }
        printf("%04d-%02d-%02d\n",year,month,day);
    }

}
// 64 位输出请用 printf("%lld")