题解 | #提取不重复的整数#

#include <algorithm>
#include <iostream>
#include <vector>
#include <string>
using namespace std;

int main() {
    vector<char> vctNUm;
    string str_s;
    cin >> str_s;
    for (auto it = str_s.rbegin(); it != str_s.rend(); ++it){
        auto it2 = find(vctNUm.begin(), vctNUm.end(), *it);
        if (it2 == vctNUm.end()) {
            vctNUm.push_back(*it);
        }
    }
    
    for (auto it = vctNUm.begin(); it != vctNUm.end(); ++it)
    {
        cout << *it;
    }
}
// 64 位输出请用 printf("%lld")