题解 | #记负均正II#
记负均正II
https://www.nowcoder.com/practice/64f6f222499c4c94b338e588592b6a62
#include <stdio.h>
int main(){
int n;
int count = 0;
float nun = 0;
int neg = 0;
while(scanf("%d", &n) != -1){
if(n < 0){
count++;
}
else if(n != 0){
neg++;
nun += n;
}
// printf("%.1f\r", nun / neg);
}
printf("%d\n", count);
printf("%.1f\n", nun / neg);
return 0;
}

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