题解 | #有序序列合并#
有序序列合并
https://www.nowcoder.com/practice/a9e943b0dab142759807d0cfb6863897
#include <stdio.h>
#define N 2000
int main() {
int num1 = 0;
int num2 = 0;
int arr[N] = { 0 };
while (2 == scanf("%d %d", &num1, &num2)) {
// 输入
for (int i = 0; i < num1 + num2; i++) {
scanf("%d", &arr[i]);
}
// 冒泡排序 :升序
int sum = num1 + num2;
for (int i = 0; i < sum; i++) {
for (int j = 0; j < sum - i - 1; j++) {
if (arr[j] > arr[j + 1]) {
int tmp = arr[j];
arr[j] = arr[j + 1];
arr[j + 1] = tmp;
}
}
}
// 输出
for (int i = 0; i < sum; i++) {
printf("%d ", arr[i]);
}
printf("\n");
}
return 0;
}
科大讯飞公司氛围 477人发布