题解 | #简单密码#

#include <iostream>
#include <string>
#include <map>
using namespace std;

int main() {
    string input;
    cin >> input;
    string dict = "22233344455566677778889999";

    string output;
    for (char c: input) {
        if (c >= 'a' && c <= 'z') output += dict[c-'a'];
        else if (c >= 'A' && c <= 'Z') output += (char)('a' + (c-'A'+1)%26);
        else output += c;
    }
    cout << output;
}
// 64 位输出请用 printf("%lld")