题解 | #牛牛的矩阵相加#
牛牛的矩阵相加
https://www.nowcoder.com/practice/730b90507602412fac90a3f106bfa0cd
n = int(input())
matrix = [[1,2,3],[4,5,6],[7,8,9]]
for i in range(len(matrix)):
for j in range(len(matrix[0])):
matrix[i][j] *= n
print(matrix)
牛牛的矩阵相加
https://www.nowcoder.com/practice/730b90507602412fac90a3f106bfa0cd
n = int(input())
matrix = [[1,2,3],[4,5,6],[7,8,9]]
for i in range(len(matrix)):
for j in range(len(matrix[0])):
matrix[i][j] *= n
print(matrix)
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