题解 | #使用3-8译码器①实现逻辑函数#
使用3-8译码器①实现逻辑函数
https://www.nowcoder.com/practice/be81e76ebade445baca7257aa4eca8f2
`timescale 1ns/1ns
module decoder_38(
input E1_n ,
input E2_n ,
input E3 ,
input A0 ,
input A1 ,
input A2 ,
output wire Y0_n ,
output wire Y1_n ,
output wire Y2_n ,
output wire Y3_n ,
output wire Y4_n ,
output wire Y5_n ,
output wire Y6_n ,
output wire Y7_n
);
wire E ;
assign E = E3 & ~E2_n & ~E1_n;
assign Y0_n = ~(E & ~A2 & ~A1 & ~A0);
assign Y1_n = ~(E & ~A2 & ~A1 & A0);
assign Y2_n = ~(E & ~A2 & A1 & ~A0);
assign Y3_n = ~(E & ~A2 & A1 & A0);
assign Y4_n = ~(E & A2 & ~A1 & ~A0);
assign Y5_n = ~(E & A2 & ~A1 & A0);
assign Y6_n = ~(E & A2 & A1 & ~A0);
assign Y7_n = ~(E & A2 & A1 & A0);
endmodule
module decoder0(
input A ,
input B ,
input C ,
output wire L
);
wire Y0_n,Y1_n,Y2_n,Y3_n,Y4_n,Y5_n,Y6_n,Y7_n ;
assign L = ~(Y1_n & Y3_n & Y6_n & Y7_n);
decoder_38 U_DECODER_38(
/*input */ .E1_n (1'b0) ,
/*input */ .E2_n (1'b0) ,
/*input */ .E3 (1'b1) ,
/*input */ .A0 (C) ,
/*input */ .A1 (B) ,
/*input */ .A2 (A) ,
/*output wire */ .Y0_n (Y0_n) ,
/*output wire */ .Y1_n (Y1_n) ,
/*output wire */ .Y2_n (Y2_n) ,
/*output wire */ .Y3_n (Y3_n) ,
/*output wire */ .Y4_n (Y4_n) ,
/*output wire */ .Y5_n (Y5_n) ,
/*output wire */ .Y6_n (Y6_n) ,
/*output wire */ .Y7_n (Y7_n)
);
endmodule
