题解 | #链表内指定区间反转#
链表内指定区间反转
https://www.nowcoder.com/practice/b58434e200a648c589ca2063f1faf58c
/**
* struct ListNode {
* int val;
* struct ListNode *next;
* };
*/
class Solution {
public:
/**
*
* @param head ListNode类
* @param m int整型
* @param n int整型
* @return ListNode类
*/
ListNode* reverseBetween(ListNode* head, int m, int n) {
// write code here
ListNode dummy(0);
dummy.next = head;
ListNode* pm = nullptr;
ListNode* pn = nullptr;
int i = 0;
for (auto ptr=&dummy; ptr; i++) {
if (m-1 == i) {
pm = ptr;
} else if (n == i) {
auto nxtPtr = ptr->next;
ptr->next = nullptr;
auto tmp2 = pm->next;
pm->next = reverseLink(pm->next);
tmp2->next = nxtPtr;
break;
}
ptr = ptr->next;
}
return dummy.next;
}
// 普通链表反转
ListNode* reverseLink(ListNode* head) {
ListNode* pre = nullptr;
for (auto ptr=head; ptr; ) {
auto nxt = ptr->next;
ptr->next = pre;
pre = ptr;
ptr = nxt;
}
return pre;
}
};
