题解 | #N个数之和#
N个数之和
https://www.nowcoder.com/practice/b007744eb43b4f7b95d9e87de01528db
#include <iostream>
#include <malloc.h>
using namespace std;
int main(void) {
int N, sum = 0;
cin>>N;
int * p = (int *)malloc(sizeof(int) * N);
for(int i = 0;i < N;++i) {
cin >> p[i];
sum += p[i];
}
cout << sum;
return 0;
}
