题解 | #字符串变形#
字符串变形
https://www.nowcoder.com/practice/c3120c1c1bc44ad986259c0cf0f0b80e
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# 代码中的类名、方法名、参数名已经指定,请勿修改,直接返回方法规定的值即可
#
#
# @param s string字符串
# @param n int整型
# @return string字符串
#
class Solution:
def trans(self , s: str, n: int) -> str:
# write code here
# 经过一遍遍历将字符串逆序,且字母大小写改变
# A 65 a 97
res = ""
s_len = len(s)
all_words = s.split(" ")
words_len = len(all_words)
for j in range(0, words_len):
word = all_words[words_len - j - 1]
for cur_ch in word:
cur_ch_num = ord(cur_ch)
new_ch = ""
if cur_ch_num >= 65 and cur_ch_num < 65 + 26:
new_ch = chr(cur_ch_num + 32)
res = res + new_ch
else:
new_ch = chr(cur_ch_num - 32)
res = res + new_ch
if j != words_len -1:
res = res + " "
return res