题解 | #求int型正整数在内存中存储时1的个数#

#include <iostream>
using namespace std;
//十进制转为二进制,统计二进制中的1的数量

int x2(int a, int count) {
    while (a > 0) {
        if (a % 2 == 1)
            count++;
        a /= 2;
    }

    return count;
}
int main() {
    int num, count = 0;
    cin >> num;
    cout << x2(num, count);
  
    return 0;
}