题解 | #记负均正II#

#include <bits/stdc++.h>
#include <cstdio>
#include <iomanip>
using namespace std;
int main() {
    int n;
    int negCount = 0;
    int average = 0.0;
    int avCount = 0.0;
    while (cin >> n) {
        if (n < 0) {
            negCount++; // 负数个数
        } else {
            // 非负数的平均值=所有非负数/非负数个数
            avCount++;
            average += n;
        }
    }
    cout << negCount << endl;
    if (avCount == 0) {
        cout << 0.0 << endl;
    } else {
        cout << fixed << setprecision(1) << average * 1.0 / avCount << endl;
    }
}