题解 | #三元操作符#

`timescale 1ns/1ns

module top_module(
    input [7:0] a, b, c, d,
    output [7:0] max);//
    
   
    //俩俩对比
    wire    [7:0]   flag1,flag2;
    assign  flag1 = (a>=b)?a:b;
    assign  flag2 = (c>=d)?c:d;

    assign  max = (flag1 >= flag2)?flag1:flag2;

endmodule

  //使用循环
    reg [7:0][3:0]buff;
    reg [7:0]temp;

    integer  i;

    always @(*)begin
        buff[0] = a;
        buff[1] = b;
        buff[2] = c;
        buff[3] = d;
        temp=buff[0];
        for(i=0;i<4;i=i+1)begin:a1
            temp =  temp > buff[i]?temp:buff[i];
        end
    end