题解 | #牛牛的矩阵相加#
牛牛的矩阵相加
https://www.nowcoder.com/practice/730b90507602412fac90a3f106bfa0cd
times=int(input()) max=[[1,2,3],[4,5,6],[7,8,9]] max=[[i*times for i in m] for m in max] print(max)
牛牛的矩阵相加
https://www.nowcoder.com/practice/730b90507602412fac90a3f106bfa0cd
times=int(input()) max=[[1,2,3],[4,5,6],[7,8,9]] max=[[i*times for i in m] for m in max] print(max)
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