题解 | #牛牛的三元组问题#
牛牛的三元组问题
https://www.nowcoder.com/practice/72c6d735fb1144a2ba162976a4510839
#
# 代码中的类名、方法名、参数名已经指定,请勿修改,直接返回方法规定的值即可
#
#
# @param nums int整型一维数组
# @return int整型二维数组
#
class Solution:
def findTriplets(self, nums: List[int]) -> List[List[int]]:
# write code here
nums.sort()
res = []
for i in range(len(nums) - 2):
# Avoid duplicates
if i > 0 and nums[i] == nums[i - 1]:
continue
left, right = i + 1, len(nums) - 1
while left < right:
total = nums[i] + nums[left] + nums[right]
if total == 0:
res.append([nums[i], nums[left], nums[right]])
while left < right and nums[left] == nums[left + 1]:
left += 1
while left < right and nums[right] == nums[right - 1]:
right -= 1
left += 1
right -= 1
elif total < 0:
left += 1
else:
right -= 1
return res
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