题解 | #最长公共子序列(一)#
最长公共子序列(一)
https://www.nowcoder.com/practice/672ab5e541c64e4b9d11f66011059498
import java.util.Arrays;
import java.util.Scanner;
// 注意类名必须为 Main, 不要有任何 package xxx 信息
public class Main {
public static void main(String[] args) {
Scanner in = new Scanner(System.in);
final int N = in.nextInt();
final int M = in.nextInt();
String s1 = in.next();
String s2 = in.next();
int[][] maxLen = new int[N + 1][M + 1];
//maxLen[i + 1][j + 1]表示以s1[i][j]子串的最长公共子序列长度
for (int i = 0; i != N; ++i) {
for (int j = 0; j != M; ++j) {
int c1 = s1.charAt(i);
int c2 = s2.charAt(j);
if (c1 == c2) {
maxLen[i + 1][j + 1] = maxLen[i][j] + 1;
} else {
maxLen[i + 1][j + 1] = Math.max(maxLen[i + 1][j], maxLen[i][j + 1]);
}
}
}
System.out.print(maxLen[N][M]);
}
}
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