题解 | #变种水仙花#

#include <stdio.h>
#include <math.h>

int isLilyNumber(int num) {
    int sum = 0;
    int yuShu;//余数
    int shang;//商
    for (int i = 1; i < 5; i++) {
        shang = num / (int)pow(10, i);//乘方，需要math.h
        yuShu = num % (int)pow(10, i);
        sum  = sum + shang * yuShu;
    }
    if (sum == num) return 1;
    else return 0;

}

int main() {
    for (int i = 10000; i < 99999; i++) {
        if(isLilyNumber(i) == 1) printf("%d ", i);
    }
    return 0;
}