题解 | #复制部分字符串#
复制部分字符串
https://www.nowcoder.com/practice/8f5b923683b94e549880e3c8370e3e55
//#include <iostream>
#include <bits/stdc++.h>
#include <stdio.h>
#include <string.h>
using namespace std;
int main() {
char str[31] = { 0 };
int m;
cin >> str;
//gets(str);//c++环境下,这个不能用
int size_old = strlen(str) + 1;
scanf("%d\n", &m);
int size_new = size_old - (m - 1);
/*初始化数组,使其每个元素都是'\0','\0'字符的ascii码就是0:https://blog.csdn.net/qq_32634545/article/details/75454017*/
char str_new[31] = {0};//后面打印用到printf字符串,所以先把每个元素初始化位\0,否则最后一个printf的字符容易出现乱码
/*用指针来实现*/
char *str_ptr = str + m -1;
char *str_new_ptr = str_new;
while( *str_ptr != '\0'){
*str_new_ptr = *str_ptr;
str_new_ptr++;
str_ptr++;
}
/*用数组来实现*/
// for(int i = 0; i < size_new; i++){
// str_new[i] = str[i + m - 1];
// }
printf("%s", str_new);
return 0;
}

