题解 | #求 1 - n 之间偶数的和#
求 1 - n 之间偶数的和
https://www.nowcoder.com/practice/03df7fa0950046a9ba564b4438f918a3
#include <iostream>
using namespace std;
int main() {
int n;
cin >> n;
int sum = 0;
// write your code here......
if (n % 2 == 1) {
n--;
}
sum = (n / 2) * (n / 2 + 1);
cout << sum << endl;
return 0;
}
