题解 | #序列重组矩阵#
序列重组矩阵
https://www.nowcoder.com/practice/7548f8f5e44c42fa84fb2323d899a966
#include <stdio.h>
int main() {
int n, m, i, j,temp,k=1;
scanf("%d %d\n",&n,&m);
int a[100] = {0};
int b[10][10] = {0};
for (i=0; i<n*m; i++)
{
scanf("%d ", &a[i]);
}
for (i = 0; i < n*m; i++)
{
for (j = 0; j < n*m-i; j++)
{
if (a[j+1]<=a[j])
{
temp=a[j+1];
a[j+1]=a[j];
a[j]=temp;
}
}
}
for (i = 0; i < n; i++)
{
for (j = 0; j < m; j++)
{
b[n][m]=a[k];
k++;
printf("%d ",b[n][m]);
}
printf("\n");
}
}
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