题解 | #牛牛的计划#

#include <stdio.h>

int main() {
    int year,month,day;
    int year0,month0,day0;
    
    scanf("%4d %d %2d\n%4d %d %2d",&year,&month,&day,&year0,&month0,&day0);
    if(year0>year)//年过
    {
        printf("yes");
    }
    else if(year0==year)//同年
    {
        if(month0>month)//月后
        {
            printf("yes");
        }else if (month0==month) {  //同月
            if(day0>day||day0==day)
            {
                printf("yes");
            }
        }
    }else { //年前
        printf("no");
    }
    return 0;
}