题解 | #简单计算器#
简单计算器
https://www.nowcoder.com/practice/b8f770674ba7468bb0a0efcc2aa3a239
#include <stdio.h>
int main()
{
double a1, a2;
char ch;
scanf("%lf%c%lf", &a1, &ch, &a2);
switch (ch)
{
case '+':
printf("%.4lf+%.4lf=%.4lf\n",a1, a2, a1+a2);
break;
case '-':
printf("%.4lf-%.4lf=%.4lf\n", a1, a2, a1-a2);
break;
case '*':
printf("%.4lf*%.4lf=%.4lf\n", a1, a2, a1*a2);
break;
case '/':
if (a2 == 0.0) printf("Wrong!Division by zero!\n");
else printf("%.4lf/%.4lf=%.4lf\n", a1, a2, a1/a2);
break;
default:
printf("Invalid operation!\n");
break;
}
return 0;
}
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