题解 | #提取不重复的整数#
提取不重复的整数
https://www.nowcoder.com/practice/253986e66d114d378ae8de2e6c4577c1
#include <iostream>
using namespace std;
const int N = 20;
int vis[N];
int main()
{
string s;
cin >> s;
for(int i = s.length() - 1; i >= 0; i --)
{
int num = (int)s[i];
if(vis[num] == 0)
{
vis[num] = 1;
cout << s[i];
}
}
cout << endl;
return 0;
}
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