题解 | #数字字符串转化成IP地址#
数字字符串转化成IP地址
https://www.nowcoder.com/practice/ce73540d47374dbe85b3125f57727e1e
import java.util.*;
public class Solution {
/**
* 代码中的类名、方法名、参数名已经指定,请勿修改,直接返回方法规定的值即可
*
*
* @param s string字符串
* @return string字符串ArrayList
*/
public ArrayList<String> restoreIpAddresses (String s) {
// write code here
//先过滤掉不符合条件的
if (s.length() < 4 || s.length() > 12) {
return new ArrayList<>();
}
StringBuilder sb = new StringBuilder();
ArrayList<String> res = new ArrayList<>();
dfs(s, sb, res, 0, 0);
return res;
}
public void dfs(String s, StringBuilder sb, ArrayList<String> res, int pointSum,
int start) {
//如果逗号数量为3,则说明分割完成了
if (pointSum == 3) {
//再对最后一层循环的字符进行判断是否合法
//左闭塞右开
String sTemp = s.substring(start, s.length());
if (isValid(sTemp)) {
sb.append(sTemp);
res.add(new String(sb.toString()));
sb.delete(sb.length() - sTemp.length(), sb.length());
// sb.setLength(sb.length() - sTemp.length());
return;
}
}
// 检查索引是否超出范围
if (start >= s.length()) {
return;
}
for (int i = start; i < s.length(); i++) {
//截取的字符
String sTemp = s.substring(start, i + 1);
//判断是否合法
if (!isValid(sTemp)) {
//不合法就结束递归
return;
} else {
// int lengthBeforeAppend = sb.length();
sb.append(sTemp).append(".");
pointSum++;
dfs(s, sb, res, pointSum, i + 1);
//记得删除逗号
// sb.setLength(lengthBeforeAppend);
sb.delete(sb.length() - sTemp.length() - 1, sb.length());
pointSum--;
}
}
}
// 校验函数
public boolean isValid(String s) {
if (s.length() == 0 || (s.charAt(0) == '0' && s.length() != 1)) {
return false;
}
int a = Integer.parseInt(s);
return a >= 0 && a <= 255;
}
}

